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-5x^2-2.4x+0.36=0
a = -5; b = -2.4; c = +0.36;
Δ = b2-4ac
Δ = -2.42-4·(-5)·0.36
Δ = 12.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{12.96}}{2*-5}=\frac{2.4-\sqrt{12.96}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{12.96}}{2*-5}=\frac{2.4+\sqrt{12.96}}{-10} $
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